solution:

First we have to dig up the equation we are going to use:

eqnarray7

tex2html_wrap_inline53 is the change in length
tex2html_wrap_inline55 is the coefficient for linear expansion
tex2html_wrap_inline57 is the length of the material
tex2html_wrap_inline59 is the change is temperature

Now we know tex2html_wrap_inline55 and the length (height) of the structure in question (Willamette Hall).
To be able to use this equation we have to change the temperatures to either Celsius or Kelvin to find the temperature difference (remember that when using a change in temperature, one Kelvin is equal to one degree Celsius).
You could either change both the temperatures to Celsius and then find the change in temperature from those two temps, but there is a trick you can use to shorten the math a bit. The temperature change is tex2html_wrap_inline71 . If comparing just temperature change, we know that one degree Celsius is equal to 9/5 of a degree Fahrenheit, so we can just multiply the 68 times 5/9 to get 37.8 degrees Celsius.
Let's see the Math of this little trick:
(subscipts 1 and 2 refer to the low and high temps respectively, and the C and F are celsius and fahrenheit)

eqnarray12

So we know that the change in temperature is (37.8K).
Now we plug in the values we know to find the change in length.

eqnarray44