Since the ball is thrown and caught at the same height above the ground, the vertical displacement is 0. We find the time it takes for the ball to go up and back to its original height:
There is no acceleration in the x-direction, so we can find the distance it goes using the time:
Since the receiver starts 10.0m away from the quarterback, he has to go 17.5m-10.0m = 7.5m in 1.29s
