solution:

Initial conditions:

eqnarray6

There is .588J of energy in this system that must remain constant at every step. We can use this number to find the conditions just before collision:

eqnarray12

Just after collision: momentum and energy are conserved so we can use the numbers from above to find the velocities of the balls just after collision.

eqnarray24

Now solve for tex2html_wrap_inline116 in equation (1) and plug it into (2) and solve for tex2html_wrap_inline118 .

eqnarray32

Use the quadratic equation:

eqnarray72

The negative velocity is correct because it clear that the ball will not rebound with a greater velocity than it started with in the the same direction.

eqnarray78

Just after collision:

eqnarray85

At max height all KE is PE = mgh

eqnarray93

tex2html_wrap122