How do we go about this exercise?
Well, the procedure is:
Seems simple. Let's do it.
Start with:
===> rho(critical) = (3 H(now)**2 / [8 pi G] )
===> rho(t) > rho(critical) - (CC/[4 pi G] = rho(critical) [ 1 - 2 CC/(3 H(now)**2) ], or
===> rho(t) + CC/(4 pi G) > rho(critical)
But before we go on, photons are in there, but why? Aren't photons massless? And what if neutrinos turn out to be massless? Why are they there?
===> mass = Energy / c**2
For the Cosmic Neutrino Background Radiation (CNBR)
====> rho(neutrinos) = U / c**2 = a T**4 / c**2 for massless neutrinos
====> rho(neutrinos) = 0.3 rho(photons) since T(neutrinos) ~ 1.9 Kelvin as compared to T(photons) ~ 2.74 Kelvin. If neutrinos are massless then the CNBR does not make a large contribution to the matter density of the Universe.
Neutrinos can either make a significant contribution to the mass of the Universe or not, depending upon whether they have a significant rest mass.
Galaxies are divided up into different types (morphological classification scheme):
The different types of galaxies have different Mass-to-Light (M/L) ratios. To get a feel for what M/L tells us, consider:
The Mass-to-Light depends on the types of stars that populate galaxies and how much unseen matter exists in the galaxies.
The typical values for the visible parts of galaxies are:
===> Omega(gal,visible) ~ 0.007 (factor of 2 uncertainty) << 1
So, if we say, pick out a star and then measure how far it is from the center of the galaxy and how fast it is moving ===> mass contained within the orbit of the star (if the mass of the galaxy is distributed spherically). This is a powerful method, for example,
===> R(Sun) ~ 25,000 light years ~ 2.5 x 10 **22 cm and V(Sun) ~ 220 km/s = 2.2 x 10**7 cm.s
===> M(Milky Way) ~ 1.8 x 10**44 grams ~ 10**11 M(Sun) !
Based upon rotation curves, one concludes that the dark matter in the halos contributes at least 3 - 10 times the mass density of the luminous parts of the galaxies ===> Omega > 0.02 --> 0.07
So, for example, for one galaxy we have (roughly speaking)
where
Result: - GM(total)/{average R}**2 + v**2/{average R} = 0 ===> M(total) ~ v**2 {average R} / G
Using galaxies, (M/L) for the cluster ~ 10 (M/L) for the luminous part of the cluster. ===> Omega(cluster) ~ 0.1 - 0.3 < 1
Recent work using faint blue objects (young galaxies at redshifts of z = 1 - 3 ?) is quite suggestive. In deep exposures of relatively distant clusters (z ~ 0.2 - 0.5), the background faint blue objects are lensed. Although, these studies are in their early stages, preliminary results give results consistent with the other more traditional ways of inferring the mass of clusters of galaxies.